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2 years ago

Need help will give brainliest i am timed answer in 20 minutes

Mathematics

1 answer:

Artist 52 [7]2 years ago

3 0

Answer:

121

The axis of symmetry is the line x= 6

The parabola opens downwards.

The value of h when the equation is in vertex form is positive.

Step-by-step explanation:

In the pictures.

Hope it helps! :)

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Which of the following represents "four times the square of a number is thirty-six"?

Lapatulllka [165]

Answer:

Option (b) is correct.

$4x^2=36$

Step-by-step explanation:

Given expression "four times the square of a number is thirty-six"

We have to write it mathematically and choose the correct options out of given options.

Consider the given expression "four times the square of a number is thirty-six"

Then

let the number be x ,

Then four times the square of a number written mathematically as $4x^2$

And given "four times the square of a number is thirty-six" written mathematically as $4x^2=36$

Therefore, "four times the square of a number is thirty-six" written mathematically as $4x^2=36$

Option (b) is correct.

6 0

3 years ago

Read 2 more answers

Points A, B, and C, form a triangle. The distance between point A and point B is 15 yards. The distance between point B and poin

Nana76 [90]

The total distance if Pete walks from A to B to C is 40 yards, the direct distance from A to C is more than 10 yards, and an inequality w < 30

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have:

Points A, B, and C, form a triangle. The distance between point A and point B is 15 yards. The distance between point B and point C is 25 yards.

Total distance if Pete walks from A to B to C:

= 15 + 25 = 40 yards

As we know in the triangle the sum of the two sides is greater than the third side.

25 + 15 > AC

40 > AC

AC < 40

The direct distance from A to C is more than 10(25-15) yards.

The inequality w < 30 represents the distance, w, that Pete might save by taking the direct path.

Thus, the total distance if Pete walks from A to B to C is 40 yards, the direct distance from A to C is more than 10 yards, and an inequality w < 30

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ1

3 0

2 years ago

On Tuesday, Gavin jogged 5 km. On Wednesday, he jogged 6.2 km, and on Thursday he sprinted 50 m. How many meters did he travel i

ankoles [38]

He jogged 61.2 km hope this helps.

4 0

3 years ago

Read 2 more answers

Carson is draining his swimming pool so he can clean it. The water level started at 12 feet and decreased 6 inches every hour. W

ra1l [238]

9514 1404 393

Answer:

Step-by-step explanation:

The units of the problem need to be consistent. Here, it is convenient to use feet. 6 inches is 1/2 foot, so the level will decrease 1/2 ft for each hour. It starts at +12 ft, and goes down from there:

y = -1/2x +12

3 0

3 years ago

4sin²<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D" id="TexFormula1" title="\frac{x}{2}" alt="\frac{x}{2}" align="absm

raketka [301]

Answer:

$\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}$

Step-by-step explanation:

Hi there!

We want to solve for $x$ in:

$4\sin^2(\frac{x}{2})=3$

Since $x$ is in the argument of $\sin^2$ , let's first isolate $\sin^2$ by dividing both sides by 4:

$\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}$

Next, recall that $\sin^2x$ is just shorthand notation for $(\sin x)^2$ . Therefore, take the square root of both sides:

$\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}$

Simplify using $\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$ :

$\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}$

Let $\phi = \frac{x}{2}$ .

<h3><u>Case 1 (positive root):</u></h3>

$\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}$

Therefore, we have:

$\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}$

<h3><u>Case 2 (negative root):</u></h3>

$\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}$

8 0

3 years ago