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valentina_108 [34]
2 years ago
14

In a classical model of the singly-ionized helium atom, a single electron orbits the nucleus in a circular orbit of radius.

Physics
1 answer:
NikAS [45]2 years ago
5 0

Yes, in a classical model of the singly-ionized helium atom, a single electron orbits the nucleus.

<h3>What is singly ionized helium?</h3>

Singly ionized helium is an atom that has lost one electrons from its outermost shell. We consider its remaining electron like a hydrogen electron. There is only one difference between a hydrogen atom and a singly ionized helium atom which is the number of protons in the nucleus so the nucleus charge on singly ionized helium is -1.

Learn more about helium here: brainly.com/question/26226232

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How do land and sea breeze work?
Studentka2010 [4]
 by the wind and air flow in the wind

7 0
4 years ago
If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swi
ddd [48]

Long straight distance that a person can swim is 5.64 m.

<h3>What is the Long straight distance?</h3>

The line that runs form one end of the circle to another is called the diameter of the circle. The pool is a circle according to the question and the long straight distance that a person can swim is the same of the diameter of the circular pool.

Now we have;

A =  πr^2

A = area of pool

r  = radius of pool

r = √A/ π

r = √25/3.142

r = 2.82m

Diameter of the circular pool = 2 r = 2 (2.82 cm) = 5.64 m

Learn more about circle: brainly.com/question/11833983

#SPJ1

Missing parts;

An ad for an above-ground pool states that it is 25 m2. From the ad, you can tell that the pool is a circle. If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swim? Express your answer in three significant figures.

3 0
2 years ago
a car traveling at 24 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds what is its acceleration?
Irina18 [472]
We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the  correct equation.

We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time  of 6 s. We and looking for acceleration (a) in m/s^2.

The following equation has everything we need:

v_f=v_i + at

So plug in the known values and solve for a:

0 = 24 + 6a

-24 = 6a

a = -4 m/s^2
8 0
4 years ago
Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another and ends up as what?
barxatty [35]

Answer:

Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Explanation:

The solar energy cycle functions in the following form:

  • Considering that 100% of energy is directed at earth.
  • When 100% light is incident on the Earth's surface about 6-7% of it is reflected back by the atmosphere into space.
  • 20% is reflected back by the clouds.
  • And about 4% is reflected back by Earth's surface.
  • 16% of solar energy is absorbed by the atmosphere, 3% is absorbed by clouds and 51% is absorbed by  land and ocean.
  • From the absorbed energy, 64% is radiated back to space from clouds and atmosphere and 6% is directly radiated back to space from earth.
  • From the radiated energy 15% is absorbed by the atmosphere and 23% is carried by the clouds and atmosphere through the latent heat in water vapor.

Therefore, absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Learn more about solar energy here:

<u>brainly.com/question/18175736</u>

#SPJ4

6 0
2 years ago
A simple pendulum 2 m long swings through a maximum angle of 30 ∘ with the vertical. part a calculate its period assuming a smal
victus00 [196]

Length of the pendulum (l) = 2 m

Acceleration due to gravity = g = 9.8 m/s^2

For small amplitude, the pendulum will undergo simple harmonic motion.

Hence, the time period of the pendulum for small amplitude = 2\pi \sqrt{\frac{l}{g} }

Now, plug the values of l and g

T = 2\pi \sqrt{\frac{2}{9.8} }

T = 2 × 3.14 × 0.451

T = 2.83 seconds

Hence, the time period of the pendulum for small amplitude = 2.83 s

3 0
3 years ago
Read 2 more answers
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