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elena-s [515]
3 years ago
13

Calculate the slope for segment 2

Physics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

23

Explanation:

The line starts at 31,  it then drops down to about 23. It then drops even  more to about 14. It then raises to 20 and then raises to 23.

Hope this helps!

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A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating along a string in the negative x-direction at
storchak [24]

Answer

given,

wavelength = λ = 18.7 cm

                    = 0.187 m

amplitude , A = 2.34 cm

v = 0.38 m/s

A)  angular frequency = ?

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

angular frequency ,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) the wave number ,

      K = \dfrac{2\pi}{\lambda}

     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

as the wave is propagating in -x direction, the sign is positive between x and t

y ( x ,t) = A sin(k  x - ω t)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75 t)

4 0
3 years ago
A 50-ohm resistor in a 0.5 Amp circuit produces how much voltage drop?​
ahrayia [7]

25 volts

Explanation:

Use Ohm's law to find the potential drop:

V = IR

= (0.5 A)(50 ohms)

= 25 volts

6 0
3 years ago
An inductor with L = 9.80 mH is connected across an ac source that has voltage amplitude 41.5 V . What value for the frequency o
sashaice [31]

Answer:

149.8Hz

Explanation:

V=I.(XL).........{1}

where (XL) is inductive reactance

(XL) =2πfL......... {2}

V= 41.5, l= 4.5, L= 9.8* 10^-³

take π to be 3.14

(XL) = V/I

= 41.5/4.5

= 9.22

f = (XL) /2πL

= 9.22* 10^³/6.28* 9.8

=149.8

7 0
3 years ago
Find the net force for <br> 10 N<br> 10 N<br> 25degree<br> 5N<br> 5N
icang [17]

Answer:

30n

Explanation:

7 0
3 years ago
The atomic number of an element is found by counting the
QveST [7]
By counting the protons in the element
6 0
3 years ago
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