D = 110 m, t = 5 s
v o = 110 cs : 5 m = 22 m/s
-------------------------------------
v = v o - a t
v = 0 m/s, v o = 22 m/s, t = 4 s
0 = 22 - 4 a
4 a = 22
a = 22 : 4
a = 5.5 m/s²
g = 9.80 m/s²
9.80 : 5.5 = 0.56
Answer:
The magnitude of its acceleration is 5.5 m/s or 0.56 g.
Answer:
hi there
Explanation:
1 - III
2- 1
3-1
HOPE IT HELP YOU
PLz mark me as a BRAINLIST
The electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
<h3>What is electric potential energy?</h3>
Electric potential energy can be defined as the energy needed to move a charge against an electric field.
It is calculated using the formula;
U = Kq1 q2 ÷ r
Where Q = electric potential energy
k = Coulombs constant
q1 and q2 = charges
r = distance of separation
Electric potential energy is inversely proportional to the distance of separation of the charges.
If the distance of the charges changes from 3mm to 6mm, then the electric potential energy of the charges is reduced because it decreases with increase in the distance of the charges.
Therefore, the electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
Learn more about electric potential energy here:
brainly.com/question/14812976
#SPJ1
Answer:
O Column 1 should be titled "Time," and Column 2 shouldbe titled "Velocity,"
O Column 1 should be titled "Velocity," and Column 2 should be titled "Time."
O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration."
O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."
KE = 1/2 mv^2 is the relationship betwee mass and kinetic energy
