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2 years ago

According to Clark Hull, our behavior is based on the need to reduce unwanted arousal

Physics

1 answer:

hammer [34]2 years ago

4 0

Answer:

Clark Hull put the emphasis of his work on experimentation, an organized theory of learning, and the nature of habits, which he argued were associations between a stimulus and a response

Explanation:

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A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i

sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, $v_{Ci}=25\ m/s$

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, $v_{Ti}=20\ m/s$

After the collision, velocity of the car, $v_{Cf}=18\ m/s$

Let $v$ is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

$initial\ momentum=final\ momentum$

$1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v$

$210000-21600=9000\ kg\times v$

$v=20.93\ m/s$

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0

3 years ago

An SUV has a mass of 6000 kg and a compact car has a mass of 2000 kg. They both go around the same unbanked circular curve on th

Evgen [1.6K]

Answer:

Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.

Explanation:

FOR SUV:

$ac_{suv} = \frac{mv^2}{r}\\$

where,

ac_suv = centripetal acceleration of the SUV = ?

m = mass of SUV = 6000 kg

v = speed of SUV = vo

r = radius of path

Therefore,

$ac_{suv} = \frac{6000\ vo^2}{r}\\$ ---------------- equation (1)

FOR CAR:

$ao = \frac{mv^2}{r}\\$

where,

ao = centripetal acceleration of the car = ?

m = mass of car = 2000 kg

v = speed of car = vo

r = radius of path

Therefore,

$ao = \frac{2000\ vo^2}{r}\\$ --------------------- equation (2)

Dividing equation (1) by eq(2):

$\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao$

Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.

8 0

3 years ago

A player hits a tennis ball in the air with an initial velocity of 32 meters per second at 35 degrees from the vertical how fast

Mamont248 [21]

Answer: 18.35 m/s

Explanation:

At the highest point of trajectory, the vertical component of the velocity would be zero and the tennis ball would have horizontal component of velocity.

It is given that the initial velocity of the ball is 32 m/s and it makes 35° with the vertical. Hence the horizontal component of the velocity,

v sin θ = 32 m/s × sin 35° = 18.35 m/s

Hence, at the highest point in its trajectory, the tennis ball would be moving with the speed 18.35 m/s.

5 0

4 years ago

Read 2 more answers

An object of mass M oscillates on the end of a spring. To double the period, replace the object with one of mass: (a) 2M. (b)M/2

harkovskaia [24]

Answer:

Explanation:

The system is a loaded spring. The period of a loaded spring is given by

$T = 2\pi\sqrt{\dfrac{m}{k}}$