Answer:
A. 3 < t < 9
Step-by-step explanation:
When the particle is moving to the right, the velocity is positive.
To find the velocity, take the derivative of s(t) with respect to t.
s(t) = -t³/3 + 13t²/2 − 30t
s'(t) = -t² + 13t − 30
Find when the velocity is 0.
0 = -t² + 13t − 30
0 = t² − 13t + 30
0 = (t − 3) (t − 10)
t = 3, 10
Check the sign of s'(t) in each interval.
0 < t < 3, s'(t) < 0
3 < t < 9, s'(t) > 0
The particle moves to the right when 3 < t < 9.
Answer:
Is there a picture of it so I can solve
Answer:
x=11 degrees,y=6
Step-by-step explanation:
Here, given ΔRWS ≅ ΔTUV
Two triangle are said to be congruent to each other it they have exactly the same three sides and exactly the same three angles.
So, here RW = UT, WS = UV and SR = VT
⇒ 25 = 3y + 7
or, 3y = 25 - 7 = 18
or, y = 18/3 = 6
⇒ y = 6
In ΔTUV
By Angle Sum Property:
∠ TUV + ∠ UVT + ∠ UTV = 180°
or, 90° + 29°+ ∠ UTV = 180°
⇒∠ UTV = 180° - 119 = 61°
Now, by congruence rule: ∠ WRS = ∠ UTV
⇒ (8x - 27)° = 61°
or, 8x = 27° + 61° = 88°
or, x = 88/8 = 11°
⇒ x = 11°
