Question

Find an equation of the plane. the plane through the point (4, 0, 1) and perpendicular to the line x = 3t, y = 3 − t, z = 7 + 9t

Answer 1

Position vector R = < 4,0,1>
(given point)

normal vector n = < 3,-1,9>

equation:
n(r-R) = 0

3(x-4) - y + 9(z-1) = 0