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2 years ago

a drawer contains 10 blue pens and 10 red pens Without looking Msr. Stanton takes 1 pen uses it and puts it back

1 answer:

Rudiy272 years ago

4 0

Answer:
1/2 if it's a probability question of getting one blue pen But there's also very little information on the question
Step-by-step explanation:

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Evaluate the following limit Lim x approaching 2 (x^2)-1/x-2

navik [9.2K]

x^2 - x - 2 is the answer

8 0

2 years ago

PLEASE HELP!! Anyone??

klasskru [66]

Replace P with 15:

d = -3(15)^2 + 168(15) - 315

d = -3(225) + 2520 - 315

d = -675 + 2520 -315

d = 1530

3 0

3 years ago

Cuidadosamente, Severina, a empregada dos “Silva” arruma uma bela cesta de maçãs. O patriarca ao ver as maçãs toma para si 1/6 d

sveticcg [70]

There was a total of 18 apples

Step-by-step explanation:

Let us consider the total no. of apples be 'a'.

Patriarca took 1/6 of the apples. So the remaining apples is,

a - (1/6) a= (5/6) a

Step 1:

His wife takes (1/5) of the rest of the apples. So after she takes the apples the remaining apples will be,

(5/6) a - (1/5) (5/6) a

(5/6) a - (1/6) a = (4/6) a

Step 2 :

Her elder son takes (1/4) of the remaining apples. So,

(4/6) a - (1/4) (4/6) a

(4/6) a - (1/6) a = (3/6) a

Step 3:

Middle son takes (1/3) of the remaining apples. So,

(3/6) a - (1/3) (3/6) a

(3/6) a - (1/6) a = (2/6) a

Step 4:

Younger son takes (1/2) of the remaining apples. So,

(2/6) a - (1/2) (2/6) a

(2/6) a - (1/6) a = (1/6) a

After work she takes the remaining 3 apples. So the remaining apples were 3

So,

(1/6) a = 3

a = 3 x 6

a = 18 apples

There were a total of 18 apples.

7 0

3 years ago

Could anyone help me with these?

lora16 [44]

Part A:

Derrick is incorrect.
A yard is equivalent to 3 feet.
Thus, 20 yards will be equivalent to 60 feet.

The width is 20 yard and 2 feet. It's the same as 60 feet and 2 feet, or 62 feet. Thus, Derrick is incorrect.

Part B:

Let's calculate the area of the parking lot.

We know the width is 62 feet from part A.
The length is 30 yards, or 90 feet.

Multiply the length and width to get the area in square feet.

$90 \times 62=5580$

The parking lot has an area of 5580 square foot.
It costs 2 dollars per square foot to repave the parking lot. Multiply the area by 2 dollars.

$5580 \times 2=11160$

It will cost $11,160 to repave the whole parking lot.

4 0

3 years ago

Read 2 more answers

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago