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Monica [59]
2 years ago
9

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
pogonyaev2 years ago
7 0

By using the general equation for a circle, we will see that the correct options are:

  • 1) This is a circle centered at (-3, - 5) with a radius of 4 units.
  • 2) The center is (-3, 5) and the radius is 2 units.
  • 3) The center is (3, 5) and the radius is 2 units.
  • 4) This is a circle centered at (3, - 5) with a radius of 4 units.

<h3>How to write a circle equation?</h3>

For a circle of radius R and center (a, b), the equation is given by:

(x - a)^2 + (y - b)^2 = R^2

With that in mind, if we look at the first equation:

(x + 3)^2 + (y + 5)^2 = 16 = 4^2

This is a circle centered at (-3, - 5) with a radius of 4 units.

For the second equation:

(x + 3)^2 + (y - 5)^2 = 4 = 2^2

The center is (-3, 5) and the radius is 2 units.

The third equation is:

(x - 3)^2 + (y - 5)^2 = 4 = 2^2

The center is (3, 5) and the radius is 2 units.

The fourth equation is:

(x - 3)^2 + (y + 5)^2 = 16 = 4^2

This is a circle centered at (3, - 5) with a radius of 4 units.

If you want to learn more about circles, you can read:

brainly.com/question/14283575

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Allie wants to take dance lessons. It costs $50 to rent the studio and $20 per lesson. If Allie has $130 for dance lessons. Up t
ludmilkaskok [199]
She would have 6 or 7 lessons 130 divided by 20 = 6.5
7 0
3 years ago
Please help me with this
Eduardwww [97]

Answer:

r^{6}

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)} , then

\frac{r^{9} }{r^{3} } = r^{(9-3)} = r^{6}

5 0
3 years ago
convert 15/9 to a decimal round your answer to the nearest hundred.convert 15/9 to a decimal round your answer to the nearest hu
motikmotik

Answer:

1.67

Step-by-step explanation:

after the decimal we have the

tens

hundreths

thousanths

(usually math doesn't ask you to go farther than the thousanths place)

because 15/9 is 1.66666, you will go to the hundreths place and round that six. Six is one more than five so it gets rounded up. That changes the decimal to 1.67.  You do not change it to 1.7, because it asked you to round to the nearest hundred not the nearest tens

6 0
3 years ago
Read 2 more answers
Use the rectangle to find x and y
sineoko [7]
Y=11 x=13
It’s a rectangle so each angle equals 90
1
Angle 1 + angle 2 =90
5y+2y+13=90
7y=77
y=11
Th diagnose of a rectangle bisect so 8x-16=5x+23
3x=39
X=13
8 0
3 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
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