3 years ago

Multiply (2x^2-3x+1)*(x^2-4x-3)

1 answer:

8 0

$(2 {x}^{2} - 3x + 1)( {x}^{2} - 4 - 3) = \\ = 2 {x}^{4} - 8 {x}^{2} - 6 {x}^{2} - 3 {x}^{3} + 12x + 9x + {x }^{2} - 4 - 3 = \\ = 2 {x}^{4} - 3 {x}^{3} - 13 {x}^{2} + 21x - 7$

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