B the goose with most mass
this is because momentum=mass x acceleration
so a larger mass will give a larger momentum ( acceleration stays constant)
Conservation of momentum requires that the sum of momenta after is equal to that before. Since initially nothing is moving, the sum after the shot will also add to zero.
m₁v₁ = -m₂v₂
Solve for the cannon's velocity v₁
v₁ = -m₂v₂/m₁ = -2.10m/s
The negative sign means it's moving 2.10m/s south.
Hydrogen is written as H2 and oxygen is written as O2
When they bond it is a covalent bond.
Hydrogen has 1 negative electron , which would attract one from oxygen, so its outer shell would have 2 electrons.
Oxygen outer shell holds 8 electrons.
The answer is
2 and 8
Answer:
Explanation:
When 2 gms of steam condenses to water at 100 degree latent heat of vaporization is releases which is calculated as follows
Heat released = mass x latent heat of vaporization
= 2 x 2260 = 4520 J
When 2 gms of water at 100 degree is cooled to ice water at zero degree heat is releases which is calculated as follows
Heat released = mass x specific heat x( 100-0)
= 2 x 4.2 x 100 = 840 J
When 2 gms of water at zero degree condenses to ice at zero degree latent heat of fusion is releases which is calculated as follows
Heat released = mass x latent heat of fusion
= 2 x 334 = 668 J
When 2 grams of steam at 100 degrees Celsius turns to ice at 0 degrees Celsius heat released will be sum of all the heat released as mentioned above ie
4520 + 840 +668 = 6028 J
