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Mnenie [13.5K]
2 years ago
8

Describe what voltage is

Physics
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

electrical 'pressure' measurement

Explanation:

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Some people say it is rare to get HIV from a blood transfusion in the United States. True or false? Why?
iragen [17]

Answer:

False

Explanation:

Because there is a 90% chance of contracting HIV from a blood transfusion

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3 years ago
The number of wave cycles that pass in one second is called the _______ of the wave.
postnew [5]

That is the frequency.

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3 years ago
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A graduated cylinder full of a clear liquid and small pieces of white material with white fumes emerging from it. Which indicato
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Answer:

A

Explanation:

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Can some one please help!!!!!!<br> ASAP pleaseeeeeeee❗️❗️❗️❗️❗️❗️❗️❗️
Thepotemich [5.8K]

a) The launch velocity of the rocket is 5.48 m/s

b) The maximum height is 1.53 m

Explanation:

a)

We can solve this part by applying the law of conservation of energy, by considering the kinetic energy and the elastic potential energy only, since there is no change in gravitational potential energy and no friction is involved.

The total energy when the spring is compressed is:

E=KE_i + PE_{si}

with

KE_i = 0 (initial kinetic energy is zero)

PE_{si} = \frac{1}{2}kx^2 is the elastic potential energy stored in the spring, with

k = 450 N/m (spring constant)

x = 0.10 m (compression of the spring)

The total energy when the spring is relased is:

E=KE_f + PE_{sf}

with

KE_f = \frac{1}{2}mv^2 (final kinetic energy), with

m = 0.15 kg (mass of the rocket)

v = velocity of launch of the rocket

PE_{sf} = 0 (elastic potential energy is zero when the spring is released)

Combining the two equations we get

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

And solving for v,

v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(450)(0.10)^2}{0.15}}=5.48 m/s

b)

In this part instead we consider only the kinetic energy and the gravitational potential energy, since the spring is at rest so its energy is now zero.

The total energy at the launch is:

E=KE_i + PE_{gi}

where

KE_i = \frac{1}{2}mv^2 (initial kinetic energy), with

m = 0.15 kg (mass of the rocket)

v = 5.48 m/s (velocity of launch of the rocket)

PE_{gi}=0 (initial gravitational potential energy is zero)

The total energy at the point of maximum height is:

E=KE_f + PE_{gf}

where

KE_f = 0 (kinetic energy is zero since speed is zero)

PE_{gf}=mgh (final gravitational potential energy), with

m = 0.15 kg

g=9.8 m/s^2 (acceleration of gravity)

h = ? (maximum height)

Combining the two equations we find

\frac{1}{2}mv^2 = mgh

And solving for h,

h=\frac{v^2}{2g}=\frac{(5.48)^2}{2(9.8)}=1.53 m

Learn more about potential energy and kinetic energy:

brainly.com/question/1198647

brainly.com/question/10770261

brainly.com/question/6536722

#LearnwithBrainly

3 0
3 years ago
A U-tube is open to the atmosphere at both ends. Water is poured into the tube until the water column on the vertical sides of t
zmey [24]

Answer:

The value is  \Delta h  =  0.003 \  m

Explanation:

From the question we are told that

   The  height of the water is  h_1  =  10 \ cm  =  0.10 \  m

    The  density of  oil is \rho_o  =  950 \  kg/m^3

  The  height of  oil  is  h_2  =  6 \ cm  =  0.06 \  m

Given that both arms of the tube are open then the pressure on both side is the same

So  

      P_a =  P_b

=>   Here  

             P_a  =  P_z + \rho_w  *  g *  h

where  \rho_w is the density of water with value  \rho_w =  1000 \ kg/m^3

and  P_z is the atmospheric pressure

and  

        P_b  =  P_z + \rho_o  *  g *  h_2

=>   P_z + \rho_w  *  g * h =    P_z + \rho_o  *  g *  h_2

=>    \rho_w   * h  =    \rho_o  *  h_2

=>      h  =  \frac{950 * 0.06 }{1000}

=>      h  = 0.057 \ m

The  difference in height is evaluated as    

           \Delta h  =  0.06 - 0.057

          \Delta h  =  0.003 \  m

     

6 0
4 years ago
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