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strojnjashka [21]
3 years ago
12

Why should you exercise caution when taking a personality test? Some online tests may ask for too much personal information. Per

sonality tests don't define exactly who you are forever. Some personality tests aren't that good. all of the above
Physics
2 answers:
noname [10]3 years ago
8 0

The correct answer is option D

All of the above


Solnce55 [7]3 years ago
5 0

Answer: all of the above

Explanation:

A personality test is the test which is done to assess the human personality. It is based on an introspective questionnaire which measures the different aspects of personality on different parameters such as behavior, likes and dislikes and others.  

The following are the cautions that are required to taken while taking a personality test:  

Some online tests may ask for too much personal information. : The online tests may ask for personal information which a person may face shame in answering thus may answer incorrectly and this will affect the reliability of the test. Thus precaution must be taken to avoid such tests.

Personality tests don't define exactly who you are forever.: As the time passes the personality also changes.  Thus these tests do not define a person exactly it is.

Some personality tests aren't that good. : Some of the personality tests do not have a reliable content which can be used to assess the personality.

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A small glass bead has been charged to 8.0 nc. what is the magnitude of the electric field 2.0 cm from the center of the bead?
astraxan [27]
<span>Charge of the glass bead Q = 8.0 x 10^-9 C Distance d = 2.0 cm = 0.02 m Coulombs constant K = 8.99 x 10^9 Nm^2/C^2 Electric Field E = k x Q / d^2 = 8.99 x 10^9 x 8.0 x 10^-9 / (0.02)^2 E = 71.92 / 0.0004 = 17.98 x 10^4 The electric field is 1.8 x 10^5 N/C</span>
7 0
3 years ago
The Earth revolves around the Sun once a year at an average distance of 1.50×1011m. Find the orbital radius that corresponds to
DedPeter [7]

Answer:

9.4\cdot 10^{10} m

Explanation:

We can solve the problem by using Kepler's third law, which states that the ratio between the cube of the orbital radius and the square of the orbital period is constant for every object orbiting the Sun. So we can write

\frac{r_a^3}{T_a^2}=\frac{r_e^3}{T_e^2}

where

r_o is the distance of the new object from the sun (orbital radius)

T_o=180 d is the orbital period of the object

r_e = 1.50\cdot 10^{11} m is the orbital radius of the Earth

T_e=365 d is the orbital period the Earth

Solving the equation for r_o, we find

r_o = \sqrt[3]{\frac{r_e^3}{T_e^2}T_o^2} =\sqrt[3]{\frac{(1.50\cdot 10^{11}m)^3}{(365 d)^2}(180 d)^2}=9.4\cdot 10^{10} m

3 0
3 years ago
A 0.150 kg ball on the end of a 1.10 m long cord (negligible mass)is swung in a vertical circle..
Aneli [31]
<span> For any body to move in a circle it requires the centripetal force (mv^2)/r. In this case a ball is moving in a vertical circle swung by a mass less cord. At the top of its arc if we draw its free body diagram and equate the forces in radial direction to the centripetal force we get it as T +mg =(mv^2)/r T is tension in cord m is mass of ball r is length of cord (radius of the vertical circle) To get the minimum value of velocity the LHS should be minimum. This is possible when T = 0. So minimum speed of ball v at top =sqrtr(rg)=sqrt(1.1*9.81) = 3.285 m/s In the second case the speed of ball at top = (2*3.285) =6.57 m/s Let us take the lowest point of the vertical circle as reference for potential energy and apllying the conservation of energy equation between top & bottom we get velocity at bottom as 9.3m/s. Now by drawing the free body diagram of the ball at the bottom and equating the net radial force to the centripetal force T-mg=(mv^2)/r We get tension in cord T=13.27 N</span>
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3 years ago
Read 2 more answers
A 50 W light bulb is plugged into a standard
wolverine [178]

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

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37.2kwh=3.39x37.2=126.108cent

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8 0
2 years ago
Why does the entropy of a gas increase when it expands into a vacuum? Why does the entropy of a gas increase when it expands int
Mrrafil [7]

Answer:

The entropy of a gas increases when it expands into a vacuum because the number of possible states increases .

Explanation:

When a gas expand in a vacuum, the molecules of the gases vibrates very fast and starting moving with higher velocity in random directions which means the level of disorder in the gases increases.

Now the possible state of the gas molecule increases such as the particle can be located at different position due to increased randomness.

<u>Entropy is the measure of this randomness and thus with this increased randomness entropy also increases.</u>

6 0
3 years ago
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