Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
Michelle(1)+bros(2)+sisters(3)+mom(1)+Pop(1)=8
3/4 of 8 = 6
So, 6 people in Michelle's family like to go swimming
Given: w²+9=6w [0, 3, 6, 9]
We need to substitute each number for w and find which works
Sub Zero: 0²+9=6×0
Simplify: 9=0. 9 does not equal 0, so it is not 0
Sub Three: 3²+9=6×3
Simplify: 9+9=18
Addition: 18=18
The statement 18=18 is true, therefore we have our answer.
Answer: The second option is correct. 3 would be the correct number to substitute to make the equation correct.
Answer:
Right now I'm wondering what kind of class you are taking to get such a weird graph, but I graphed it for you on the screenie.
Step-by-step explanation:
You should though recheck your question for exponents, as 9x2 could be interpreted differently.
Since exponents to not transition well here, I can assume that it was a 9x^2, so please add an exponent symbol ^ between the variables and exponents next time.