Simplified it's 576x^8y^7
That's an awfully broad question. Could you not be more specific?
A basic example: Suppose you are told that sin theta = 1/2. Solving this equation would require finding the measure of the angle theta. In this case the answer would be "30 degrees," or "pi/6 radians."
Answer:
please give me brainlest
Step-by-step explanation:
16 is the answers for the question
Length of AC is 5 I hope this helps I can’t think right right now so bare with me

Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19
Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.
Estimate of sample mean

Estimate of sample standard deviation


to 5 decimal places.
Thus, using the normal probability table,





Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=
0.0712858