Answer:
2 hours and 28 mins
Step-by-step explanation:
75-15=60=1 hour remain 15 mins
45+14=63-3=60=1 hour remain 3 mins
3+25=28 mins remain 0 mins
total= 2hours and 28 mins
plz mark me brainly .
6(n+8)=2
6n + 48 = 2
6n + 48 - 48 = 2 - 48
6n = -46
N = -46/6
N = -7 2/3
Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
So work =time times rate or W=TR
so T=m-k
W=(m-k)R
if you want just m-k then m-k is the answer
-3z + 7 = -7 - 10z
Add 10z to both sides
7z + 7 = -7
Subtract 7 from both sides
7z = -14
Divide by 7
Z = -2
