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Lena [83]
3 years ago
5

Help

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Using linear function concepts, it is found that the change in the breaking weight of the pennies was of -6 units of weight.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, the function is:

y = -6x + 136.

The slope is of m = -6, hence the change in the breaking weight of the pennies was of -6 units of weight.

More can be learned about linear function concepts at brainly.com/question/24808124

#SPJ1

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Given the points (0,1) and (-2,5) and on a line, find its equation in the form y= mx+b.
AnnZ [28]

Answer:

the desired equation is y = -2x + 1

Step-by-step explanation:

As we go from (-2, 5) to (0, 1), x increases by 2 and y decreases by 4.  Thus, the slope of this line is m = rise / run = -4 / 2, or m = -2.

Starting with y = mx + b, insert the knowns:

1 = -2(0) + b.  Then b = 1, and the desired equation is y = -2x + 1.

8 0
3 years ago
Why do you think it’s important for students to learn about math
marissa [1.9K]

Answer:

Step-by-step explanation:

Math is in our everyday lives. We calculate and use math in our daily lives without knowing it. By learning math, we build on useful knowledge that will help us have a better future. For example, learning how to pay taxes acquire math. Grocery shopping needs you to find the cost of the product you’re buying. When we learn math, we gain knowledge and we can pass that knowledge to our future generations so more and more people can use it to find better jobs, make your life easier, and so much more. Therefore, that is why it is important for students to learn about math.

8 0
3 years ago
Read 2 more answers
Akira is a salon owner. Yesterday, she did 2 haircuts and colored the hair of 1 client, charging a total of $194. Today, she did
joja [24]

Answer:

\boxed {\boxed {\sf Haircut: \$47 \ and \  Color: \$ 100}}

Step-by-step explanation:

Let's set up a system of equations. (1 equation for yesterday and 1 for today).

  • Let h = haircut and c= color

2h+1c= 194  (Yesterday: 2 haircuts and 1 color for $194).

2h+4c= 494 (Today: 2 haircuts and 4 colors for $494).

Notice that both equations have a 2h. If we subtract the two equations, the 2h will cancel and leave us with one variable, c.

\ \ (2h+1c=194) \\-  (2h+4c=494)

\ \ 1c=194 \\- (4c=494)

-3c= -300

Since we are solving for c, we must isolate the variable. It is being multiplied by -3. The inverse of multiplication is division. Divide both sides by -3.

-3c/-3=-300/-3 \\c= -300/-3 \\c=100

Now we have to solve for h. Plug 100 in for c in the first equation.

2h+1(100)= 194 \\2h+100=194

100 is being added, so we must subtract 100 from both sides.

2h+100=194-100 \\2h=94

h is being multiplied by 2, so we divide both sides by 2.

2h/2=94 \\h=47

A haircut costs $47 and a color costs $100.

6 0
3 years ago
A family of 3 children and 2 adults visited a health club. The club charges $y an hour for each child and $x an hour for each ad
marishachu [46]

Answer:  Line joining ordered pairs (0, 10) and (15, 0) and Shade the portion of the graph below this line which lies within the first quadrant.

Step-by-step explanation:

Here, The club charges $y an hour for each child and $x an hour for each adult.

And, according to the question,

In the family 3 children and 2 adults visited a health club such that  the family does not want to spend more than $30 an hour at the health club.

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That is, the inequality must contains the origin.

Therefore, shaded region will occur below the line.

Also, x-intercept of the given line is (15,0)

And, y-intercept of the given line is (0,10)

Thus the line will join the order pairs (15,0) and (0,10)

Also, x\geq 0 and y\geq 0 ( because charges can not be negative)

Therefore the shaded region will only contain the first quadrant.

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musickatia [10]
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