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emmasim [6.3K]
2 years ago
8

Please help I will give brainliest.

Mathematics
1 answer:
irinina [24]2 years ago
6 0

Answer:

t = 1 sec   5 meters

Step-by-step explanation:

When the object hits the ground , height = 0

   0    = (5t+5)(1-t)      so t = -1(throw out...can't have negative time value) or 1  

As the object is dropped, t = 0    sub that in to the equation

h = (5(0)+5)(1-0) = 5 meters  

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The rectangle below has an area of 70 square meters.
nasty-shy [4]

Answer:

The side lengths are 10 by 7

Step-by-step explanation:

The area of a rectangle is

A = l*w

70 = (x - 11)(x - 8)

FOIL

70 = x^2 -8x-11x+88

Combine like terms

70 = x^2 -19x +88

Subtract 70 from each side

0 = x^2 -19x +88-70

0 = x^2 -19x+18

Factor

What number multiplies to 18 and adds to -19

-18*-1 =18

-18-1 = -19

0=(x-18)(x-1)

Using the zero product property

x-18=0   x-1=0

x=18   x=1

But x cannot x=1 because then the side lengths would be negative

x-18 = 10

x-11 = 7

The side lengths are 10 by 7

4 0
3 years ago
I’m so confused. I think it’s aas but idk
xz_007 [3.2K]
It would be asa they have 2 congruent sides, 2 angles, and they both share QS and by the reflexive prop QS=QS so it would be asa
5 0
4 years ago
Please helps, it’s evaluating. <br><br> Thank you.
-BARSIC- [3]

Answer:

the answer for the question is 5/28

7 0
3 years ago
Read 2 more answers
red bike is traveling south, toward Lawrence, at constant speed of 24km/h and a blue bike is also traveling east, away from Lawr
zavuch27 [327]

Answer:

a.R=10-24t

b.B=6+6t

Step-by-step explanation:

We are given that

Speed of red bike, v=24 km/h

Speed of blue bike, v'=12km/h

Distance of red bike when t=0

=10 km north

Distance of blue bike when t=0

=6km east

a. We have to find the expression of distance of red bike from Lawrence.

Distance=speed\times time

Let t be the time taken by red bike

Distance of red bike from Lawrence is given by

R=10-24\times t

R=10-24t

b.

Distance of the blue bike from Lawrence

B=6+6\times t

B=6+6t

5 0
3 years ago
In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports. A student is
blondinia [14]

Answer:

  18/25 = 72%

Step-by-step explanation:

P(B ∪ F) = P(B) + P(F) - P(B ∩ F)

  = 12/25 + 11/25 - 5/25

  = 18/25

The probability a randomly chosen student plays either sport is 18/25 = 72%.

3 0
4 years ago
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