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Gemiola [76]
4 years ago
8

In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports. A student is

chosen randomly from this group. What is the probability that the student plays either basketball or football?
Mathematics
1 answer:
blondinia [14]4 years ago
3 0

Answer:

  18/25 = 72%

Step-by-step explanation:

P(B ∪ F) = P(B) + P(F) - P(B ∩ F)

  = 12/25 + 11/25 - 5/25

  = 18/25

The probability a randomly chosen student plays either sport is 18/25 = 72%.

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Answer:

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Step-by-step explanation:

step 1

Find the value of y

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

In this problem

m∠A+m∠B+m∠C=180°

substitute the given values

90\°+(y+40)\°+(3y-10)\°=180\°

Solve for y

4y+120=180

4y=180-120

4y=60

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step 2

<em>Find the measure of angle B</em>

m∠B=(y+40)°

substitute the value of y

m∠B=(15+40)=55°

step 3

<em>Find the measure of angle C</em>

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substitute the value of y

m∠C=(3(15)-10)=35°

The three interior angles are different

so

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therefore

The right triangle ABC is scalene

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Diano4ka-milaya [45]
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Part A is explained with the answer.
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