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Nataliya [291]
2 years ago
12

An old car has to travel a 2-mile route, uphill and down. Because it is so old, the car can climb the first mile, the ascent, no

faster than an average speed of 15 mi/h. How fast does the car have to travel the second mile, on the descent, to achieve an average speed of 30 mi/h for the trip
Mathematics
1 answer:
Molodets [167]2 years ago
3 0

Answer:

2s + 30 = 2s

Step-by-step explanation:

Time up hill + time down hill = total time

:

Multiply equation by 30s; results

2s + 30 = 2s

:

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What is the integer closest to zero?
ANEK [815]

Answer:

The answer is 25

Step-by-step explanation:

What I would is to first divide 78 by 3. That will get you 26. Then add one to get 27, subtract one to get 25. 25+26+27=78

The answer is 25.

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Determine whether the number is a perfect square P.S there is a lot
mihalych1998 [28]

Answer:

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6 0
3 years ago
A prism is a 3d shape with the same _______ all the way through
Aloiza [94]

Answer:

cross-section

Step-by-step explanation:

prism is a type of three-dimensional (3D) shape with flat sides.

It has the same cross-section all along the shape from end to end; that means if you cut through it you would see the same 2D shape as on either end.

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A 81​-inch board is cut into two pieces. One piece is two times the length of the other. Find the length of the shorter piece.
lisov135 [29]
Piece #1: 20.25 in

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5 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 7x6, y
IgorC [24]

Answer:

The volume is \frac{490\pi}{39} cubic units.

Step-by-step explanation:

The given curve is

y=7x^6

The given line is

y=7x

Equate both the functions to find the intersection point of both line and curve.

7x^6=7x

7x^6-7x=0

7x^6-7x=0

7x(x^5-1)=0

7x=0\rightarrow x=0

x^5-1=0\rightarrow x=1

According to washer method:

V=\pi \int_{a}^{b}[f(x)^2-g(x)^2]dx

Using washer method, where a=0 and b=1, we get

V=\pi \int_{0}^{1}[(7x)^2-(7x^6)^2]dx

V=\pi \int_{0}^{1}[49x^2-49x^{12}]dx

V=49\pi \int_{0}^{1}[x^2-x^{12}]dx

V=49\pi [\frac{x^3}{3}-\frac{x^{13}}{13}]_0^1

V=49\pi [\frac{1^3}{3}-\frac{1^{13}}{13}-(0-0)]

V=49\pi [\frac{1}{3}-\frac{1}{13}]

V=49\pi (\frac{13-3}{39})

V=49\pi (\frac{10}{39})

V=\frac{490\pi}{39}

Therefore the volume is \frac{490\pi}{39} cubic units.

5 0
3 years ago
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