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oee [108]
3 years ago
8

Grant is a member of a book club. He pays a $10 yearly membership fee and can purchase books through the club for $2.75 each. Hi

s total annual cost is a function of the number of books, b, that he purchases in a year: C(b) = 2.75b + 10 Which statements are true about the variables in the yearly cost function? Check all that apply. A. The number of books purchased is the independent variable. B. The input is the yearly cost. C. The total yearly cost depends on the number of books purchased. D. The number of books purchased is determined by the yearly cost. E. The output is the yearly cost.
Mathematics
2 answers:
ryzh [129]3 years ago
5 0

Answer: A, C, and E

Step-by-step explanation:

Hi, to answer this question we have to analyze the function given:

C(b) = 2.75b + 10

Where:

  • Independent variable: b (number of books)
  • Input = b
  • Output = C = annual cost
  • Dependent variable = C (depends on b, the independent variable)

So:

A. The number of books purchased is the independent variable. TRUE  

B. The input is the yearly cost. (FALSE, the input is the number of books )

C. The total yearly cost depends on the number of books purchased. TRUE

D. The number of books purchased is determined by the yearly cost. FALSE , the yearly cost is determined by the number  

of books.

E. The output is the yearly cost.TRUE

galben [10]3 years ago
4 0

Answer:

A)The number of books purchased is the independent variable.

C)The total yearly cost depends on the number of books purchased.

E)The output is the yearly cost.

those are your corrected answers

Step-by-step explanation:

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How many positive integers under 50 are multiples of neither 4 nor 6
lyudmila [28]
Candidates range from 1 to 50.
50/4=12 positive integers are multiples of 4
50/6=8 positive integers are multiples of 6
50/12=4 positive integers are multiples of 12 (LCM of 4 and 6)
By the inclusion/exclusion principle, the number of multiples of either 4 or 6 is equal to 12+8-4=16.

Therefore, the complement is the number of positive integers that are multiples of neither 4 nor 6 = 50-16=34.


6 0
3 years ago
Find the sum.<br> (n+8)+(n−12)<br> =
WARRIOR [948]
Your answer is:
2n-4

Step by step:
(n+8)+(n-12)
Rewrite and remove the parentheses

n+8+n-12
Calculate

Therefore your solution is:
2n-4
4 0
3 years ago
Read 2 more answers
I need help finding this problem
hichkok12 [17]
The problem is in the picture that you showed
7 0
3 years ago
2. Investigate the equation y=x2-3.
Feliz [49]
Swap the sides so that all the terms of the variables are on the left side

x2+3=y

Subtract 3 from both sides

x2=y-3
8 0
1 year ago
Find the quadratic function passing through the points (0,-3), (1,2), and (2,-1)
user100 [1]

<u>Answer:</u>

The quadratic function passing through the points (0,-3), (1,2), and (2,-1) is \mathrm{f}(\mathrm{x})=-4 x^{2}+9 x-3

<u>Solution: </u>

Given that required function is quadratic  

And function is passing through points (0 , -3) , (1 , 2) and (2 , -1)

General form of a quadratic function is  f(x)=a x^{2}+b x+c ----(A)

f(x) is nothing but output value that is y.

That is f(x) = y

So y=a x^{2}+b x+c  --- (1)

Let’s use equation (1) to get required function.

Given that function passes through (0 , -3) means when x = 0 , y = -3

On substituting value of x and y in equation (1) we get  

-3=\mathrm{a}(0)^{2}+\mathrm{b}(0)+\mathrm{c}

-3 = 0 + 0 + c

c = -3

On substituting value of c in equation (1) we get  

y=a x^{2}+b x-3 ---(2)

Function also passes through point (1, 2) that is at x = 1 , y = 2.

On substituting value of x and y in equation (2) we get  

2=\mathrm{a}(1)^{2}+\mathrm{b}(1)-3

2 = a + b – 3

a + b = 5                

b = 5 - a   -------(3)

Also given function passes through point ( 2 , -1) means when x = 2 , y = -1

On substituting value of x and y in equation (2) we get  

-1=\mathrm{a}(2)^{2}+\mathrm{b}(2)-3

-1 = 4a + 2b – 3

4a + 2b = 2

2a + b = 1  ------- (4)

On substituting value of b from equation (3) in equation (4), we get

2a + (5 - a ) = 1  

a + 5 = 1

a = 1-5 = -4

From equation (3) b = 5 – a = 5 – (-4) = 9

b = 9

Now we have a = -4, b = 9 and c = -3

On substituting calculated values of a, b, and c in equation (A) we get

f(x)=-4 x^{2}+9 x-3

Hence required quadratic function is f(x)=-4 x^{2}+9 x-3

8 0
3 years ago
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