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Elina [12.6K]
2 years ago
8

The dot plots show rainfall totals for several spring storms in highland areas and lowland areas.

Mathematics
2 answers:
Marysya12 [62]2 years ago
4 0

Answer:

30 and 26

Step-by-step explanation:

ziro4ka [17]2 years ago
3 0

Answer:

Part A)  <u>Option c) 15.27 mm</u>

Part B)   <u>Option b) 12.05 mm</u>

Step-by-step explanation:

The mean is also sometimes called the average

To find the mean, you add up every number in the data set, and you divide that sum by the total number of data points within the set.

A) What is the mean rainfall for the highland storms?

The sum of the data of Highlands storms

= 2*2 + 3*4 + 2*6 + 3*8 + 4*10 + 3*12 + 4*14 + 5*16 + 5*18 + 4*20 + 2*22 + 24 + 2*26 + 2*28 + 30 + 32 = 672

the total number of data = 44

Mean = 672/44 = 15.27 mm

So, the answer is <u>option c) 15.27 mm</u>

B) What is the mean rainfall for the lowland storms?

The sum of the data of Lowland storms

= 3*2 + 5*4 + 3*6 + 3*8 + 5*10 + 7*12 + 6*14 + 4*16 +2*18 + 20 + 2*22 + 24 + 2*28 = 530

the total number of data = 44

Mean = 530/44 = 12.05 mm

So, the answer is <u>option b) 12.05 mm</u>

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Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
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Answer:

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p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

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We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

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Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

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