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tresset_1 [31]
3 years ago
7

An elliptical track has a major axis that is 50 yards long and a minor axis that is 44 yards long. Find an equation for the trac

k if its center is (0, 0) and the major axis is the x-axis.
Mathematics
1 answer:
Luden [163]3 years ago
8 0
Do It Have a Pictures
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In a parallelogram ABCD , the bisector of angle A bisects BC at X. Prove that AD=2 AB.
erica [24]
There's no diagram, so I made my own.
But I can't prove AD = 2*AB

7 0
3 years ago
Evaluate 9/g+2h+5 when g=3 and h=6
vladimir1956 [14]
To answer this question, simply input the values for g and h:

9/ (3) + 2 (6) + 5 = 9/ 3 + 12 + 5
                           = 9/ 20
          

Hope this helps!
6 0
3 years ago
Read 2 more answers
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Oliga [24]

Answer:

\displaystyle 1)48.2    \:  \: \text{sec}

\rm \displaystyle  2)3021.6 \: m

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

\displaystyle  - 4.9 {t}^{2}  + 229t + 346 = 0

to solve the equation can consider the quadratic formula given by

\displaystyle x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4 ac} }{2a}

so let our a,b and c be -4.9,229 and 346 Thus substitute:

\rm\displaystyle t =  \frac{ - (229) \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

remove parentheses:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

simplify square:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}

simplify multiplication:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 6781.6} }{ - 9.8}

simplify Substraction:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 45659.4} }{ - 9.8}

by simplifying we acquire:

\displaystyle t = 48.2  \:  \:  \: \text{and} \quad  - 1.5

since time can't be negative

\displaystyle t = 48.2

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

\displaystyle x _{  \text{max}} =  \frac{ - b}{2a}

let a and b be -4.9 and 229 respectively thus substitute:

\displaystyle t _{  \text{max}} =  \frac{ - 229}{2( - 4.9)}

simplify which yields:

\displaystyle t _{  \text{max}} =  23.4

now plug in the maximum t to the function:

\rm \displaystyle  h(23.4)- 4.9 {(23.4)}^{2}  + 229(23.4)+ 346

simplify:

\rm \displaystyle  h(23.4)  =  3021.6

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0
2 years ago
What ratio is equivalent to 21/35
eimsori [14]
A 2:5 ratio. Because 21 divided by 7 equals 3 and 35 divided by 7 equals 5. And I did it by 7 because thats common factor
4 0
2 years ago
Select all the correct answers.
ohaa [14]

Answer:

Lines 3 and 4

Step-by-step explanation:

ignore this rjrjrjrjrrnrnnrnrrnnr

8 0
3 years ago
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