PLEASE HELP IN MATH MADDD POINTS

Mathematics

1 answer:

lions [1.4K]3 years ago

3 0

Hello, scatterplots are made of bivariate data. With bivariate data, we have two sets of related data we want to compare.

So with bivariate data, we are interested in comparing the two sets of data and finding any relationships.

Hope this helps! :-)

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What is the slope of (-4,13) and (6,-2)

antiseptic1488 [7]

Answer:You already have the slope add a x on the 4.13 and y on 6,-2.

Step-by-step explanation:

3 0

3 years ago

Solve the system of linear equations by substituting. Check your solution

Ghella [55]

QUESTION 4

The given system of linear equations are,

$y = 5x - 7...(1)$

and

$- 3x - 2y = - 12...(2)$

We put equation (1) into equation (2) to obtain,

$- 3x - 2(5x - 7) = - 12$

We expand to get,

$- 3x - 10x + 14 = - 12$

Group like terms to get,

$- 3x - 10x = - 12 - 14$

Simplify to get,

$- 13x = - 26$

Divide both sides by -13 to get,

$x = 2$

Put the value of x into equation (1) to get,

$y = 5(2) - 7$

$y = 10 - 7 = 3$

The solution is

$x = 2 \: \: and \: \: = 3$

QUESTION 5

The given system of linear equations are

$-4x+y=6....(1)$
and

$-5x-y=21...(2)$

We make y the subject in equation (1) to get,

$y = 4x + 6....(3)$

Put equation (3) into equation (2) to get,

$- 5x - (4x + 6) = 21$

We expand to get,

$- 5x - 4x - 6 =21$

We group like terms to get,

$- 5x - 4x = 21 + 6$

This implies that,

$- 9x = 27$

We divide both sides by -9 to get,

$x = - 3$

Put the value of x in to equation 3 to get,

$y = 4( - 3) + 6$

$y = - 12 + 6 = - 6$

Therefore the solution is

$x = - 3 \: and \: y = - 6$

QUESTION 6

The given equations are,

$-7x-2y=-13...(1)$

and

$x-2y=-13...(2)$

Make x the subject in equation (2) to get,

$x = 2y - 13...(3)$

Put equation (3) into equation (1) to get,
$- 7(2y - 13) - 2y = - 13$

We expand to get,

$- 14y + 91 - 2y = - 13$

We group like terms to obtain,

$- 14y - 2y = - 13 - 91$

.Simplify to get,

$- 16y = - 104$

Divide through by -16 to get,

$y = \frac{13}{2}$

Put the value of y into equation (3) to get,

$x = 2( \frac{13}{2} ) - 13$

$x = 13 - 13 = 0$

Therefore

$x = 0 \: and \: y = \frac{13}{2}$