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kondor19780726 [428]
2 years ago
9

Express the interval using two different representations. (−∞,−6]

Mathematics
1 answer:
stepladder [879]2 years ago
6 0

Interval simply represent the set of numbers containing all numbers between any two numbers.

The representations of (-\infty, -6] are \{x| x \in R, x \le -6 \} and x \le -6

From the question, we have:

(-\infty, -6]

The above representation is in interval notation.

The interpretation is that;

The highest number in the interval is -6

The equivalent using set notation is:

\{x| x \in R, x \le -6 \}

The equivalent using inequalities is:

x \le -6

Read more about intervals at:

brainly.com/question/17249352

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A cone has a radius of 4 units and a height of 6 units.
zubka84 [21]

Answer:

Volume of the cone: 32π cubed unit

Step-by-step explanation:

Volume of cone: V=1/3hπr²

1/3 x 6 x π x 4^2 = 32π

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Find the surface area of a rectangular prism with a height of 6 inches, a width of 7 inches, and a length of 13 inches.
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Which transformation moves all points the same distance in the same direction?
Lesechka [4]

Answer:

In a translation, ALL of the points move the same distance in the same direction. A translation is called a rigid transformation or isometry because the image is the same size and shape as the pre-image.

Step-by-step explanation:

5 0
3 years ago
( 8n - 3n^4 + 10n ^2 ) - ( 3n^2 + 11n ^4 - 7)
DanielleElmas [232]

Answer:

-14n^4 + 7n^2 + 8n + 7

Step-by-step explanation:

( 8n - 3n^4 + 10n^2 ) - ( 3n^2 + 11n^4 - 7)

8n - 3n^4 + 10n^2 - 3n^2 - 11n^4 + 7

- 14n^4 + 7n^2 + 8n + 7

3 0
2 years ago
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An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T
Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

6 0
3 years ago
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