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vagabundo [1.1K]
4 years ago
8

How many dots would be in the 50th figure?

Mathematics
2 answers:
Alla [95]4 years ago
6 0
There would be 120 dots in the 50th figure.

algol [13]4 years ago
4 0
120 dots in a 50th figure thass the answer

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The area of the rectangular painting is
MissTica

Answer:

(x-8)

Step-by-step explanation:

you can test with FOIL, use division or synthetic division

6 0
3 years ago
11. Find the solutions of x^2-x-30 = 0.
asambeis [7]

To find the solutions of quadratic equation, there are two ways to do which are:

  • Factorize
  • Quadratic Formula

<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u>

- Factor the expression.

To factor the expression, refer below:

\displaystyle \large{ (x - a)(x - b) =  {x}^{2}  - bx - ax + ab}

For bx and ax, both can be common-factored. Therefore

\displaystyle \large{ (x - a)(x - b) =  {x}^{2}  - (b  +  a)x + ab}

From the above, we conclude that:

  • The middle term is b+a
  • The last term is a×b
  • Thus, we have to find two numbers that satisfy a+b and a×b

From the expression, 30 comes from 5×6 and when 5-6 = -1. Therefore, a can be 5 and b can be 6.

\displaystyle \large{{x}^{2}  - x - 30 = (x  +  5)(x - 6)}

Because in the middle term, it is -x which is negative, we have to let the highest number become negative.

From the factored expression:

  • The middle term = 5x + (-6x) = -x
  • The last term = 5 × (-6) = -30

Then we replace the standard equation with factored form.

\displaystyle \large{ (x  +  5)(x - 6) = 0}

For this part, we solve like a linear equation where we isolate x. Just think you are solving two linear equations!

Hence

\displaystyle \large{ x =  - 5, 6}

Therefore, the solutions are x = -5, 6.

7 0
3 years ago
What is the solution set of the equation 8x+2=x+4x−6 ?
lara31 [8.8K]

8x+2=x+4x-6\\\\8x+2=(x+4x)-6\\\\8x+2=5x-6\qquad\text{subtract 2 from both sides}\\\\8x=5x-8\qquad\text{subtract 5x from both sides}\\\\3x=-8\qquad\text{divide both sides by 3}\\\\\boxed{x=-\dfrac{8}{3}}

5 0
4 years ago
Read 2 more answers
Find sin(cx) in the triangle.<br> A. 20/29. <br> B. 20/21 <br> C. 21/29<br> D. 21/20
Anestetic [448]

Answer:

{\small{\mathcal{\underline{\underline{\blue{ here \: is \: your \: solution...}}}}}} \\ \\  \small\mathfrak\purple{ \sin( \alpha  =  \: perpendicular \div hypotenuse \:   )  } \\  \\ \small\mathfrak\purple{  =  \: perpendicular = 20  )  } \\  \\ \small\mathfrak\purple{  \:  hypotenuse = 29 \:   )  } \\  \\ \small\mathfrak\purple{ \sin( \alpha  = 20 \div 29}) \\  \\ {\small{\mathcal{\underline{\underline{\red{ hope \: it \: helps...}}}}}}

3 0
3 years ago
thanks guys for helping me. 33 down, 17 left to go!!!! i didnt realize how many ive done already! Thank you!!!!!
Lunna [17]
The answer is C
{5, 6, 7, 8, 9, 10}

oh and the question below that is B
because 28 / 7 is 4 so
x > 4
5 0
3 years ago
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