Question

Consider z1 = 4 – 4 startroot 3 endrooti and z2 = –16i. What is z1 – z2? 4 – 12startroot 3 endroot i 4 12startroot 3 endroot i 4 – 4( startroot 3 endroot – 4)i 4 4 (startroot 3 endroot – 4)i

Answer 1

The answer is: $z_1-z_2=4-4(\sqrt{3i} -4i)$

The correct option is: (D)

What are Complex numbers?

A complex number is the sum of a real number and an imaginary number. A complex number is of the form a + ib and is usually represented by z. Here both a and b are real numbers. The value 'a' is called the real part which is denoted by Re(z), and 'b' is called the imaginary part Im(z).

Since we have given : $z_1=4-4\sqrt{3i}$ and $z_2 = -16i$

The difference of z1 - z2 would be:

So,

$z_1-z_2=4-4\sqrt{3i} - (-16i)$

$z_1-z_2=4-4\sqrt{3i}+16i$

$z_1-z_2=4-4(\sqrt{3i} -4i)$

Hence, $z_1-z_2=4-4(\sqrt{3i} -4i)$

Learn more about Complex Number here:

brainly.com/question/14028757

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