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ipn [44]
2 years ago
10

Need help please and thank you

Mathematics
1 answer:
viktelen [127]2 years ago
4 0
The answer is B) -x^2-3
This is because you have an exponential graph that is flipped, hence the negative sign, and down 3.
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What is the value of the expression
Neko [114]

Hello!

Answer:

12(3+4+5+...+12+13)= 1,056

Step-by-step explanation:

After evaluating the expression it gave me : 1,056          

Hope this helps!  

3 0
3 years ago
Please help me<br><br> Determine the value of base b if (152)b = 0x6A. Please show all steps.
egoroff_w [7]

Answer:

The value of b is, 8

Step-by-step explanation:

To determine the value of b:

Given:

(152)_b = 0x6A               ....[1]

Since, 0x6A represents the hexadecimal form.

To convert this hexadecimal form into decimal form:

(6A)_{16}= (6 \times 16^1)+(A \times 16^0)=(6 \times 16)+(10 \times 1) =96+10 = 106

⇒0x6A=106(decimal form)

Now we have to convert this decimal form into octal

8  |  106

8   |  13   | 2

    |   1    |  5

        1

Then, the octal form we get, (152)_8

Substitute this in [1] we have;

(152)_b = (152)_8

On comparing both sides we have;

b = 8

Therefore, the value of b is, 8

5 0
3 years ago
I need help with this ^^ <br> It’s about choosing a graph to fit a narrative
jenyasd209 [6]
1. The fourth graph: D
2. The first graph: A
3 0
3 years ago
Pam scores n goals. Leo scored 5 fewer than Pam. Write an expression in simplest form to represent the total number of goals sco
Naddik [55]

Answer:

h

Step-by-step explanation:

3 0
3 years ago
Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.004p=7ln⁡q−3ln⁡p+0.004p=7, where q is
olga2289 [7]
  <span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q: 

(1/q)(dq/dp) − 3/p + 0.003 = 0 
dq/dp = (3/p − 0.003)q. 

So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p. 

b) The revenue is pq. 
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1: 

3 − 0.003p = −1 
0.003p = 4 
p = 4/0.003 = 4000/3 = 1333.33</span>
8 0
3 years ago
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