H=(√3)*a/2 = 41.2
So, a=2*41.2/√3=47.6
The best answer I believe is t - 2
The answer is: Hint
You welcome buddy
Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,

Substituting the values we get

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
hard to tell but from 0.75 to 1