All categories

2 years ago

If anybody known the answer plzz help me with this??

Chemistry

1 answer:

Fantom [35]2 years ago

6 0

Answer:

Select the text you want to modify.

Click the drop-down arrow next to the Font Size box on the Home tab. A drop-down menu appears.

Select the desired font size from the menu. Alternatively, you can type the value you want and then press Enter on your keyboard.

You might be interested in

How could you separate barium sulfate baso4 from nacl

Montano1993 [528]

Answer:

The answer to your question is below

Explanation:

Barium sulphate (BaSO₄) is white solid crystal inorganic compound that is odorless and insoluble in water.

Sodium chloride (NaCl) is also a white solid crystal inorganic compound odorless and soluble in water.

The, if we try to separate a mixture of these compounds we can do it by dissolving them in water, NaCl will dissolve and BaSO₄ will precipitate.

Later, we can filtrate the sample to obtain the BaSO₄, in a filtrate paper, and the NaCl will be obtain by evaporation.

5 0

3 years ago

Balance the following chemical equation:<br> P4(s)+ O2(g) - P4 O10 (s)

erica [24]

Answer:

The balanced chemical equation is P₄ (s) + 5O₂ (g) → P₄O₁₀ (s)

Explanation:

In order to balance the chemical equation, you first need to see what's out of balance.

In this case our Oxygen is not balanced, so in order to make the two the same, we need to see what coefficient we need to add to the compounds to balance the problem.

So, adding a coefficient of 5 to the O₂ will result in an equal number of oxygen on both sides.

6 0

3 years ago

Read 2 more answers

Determine the ph of a 0.500 m hno2 solution. Ka of hno2 is 4.6 × 10−4.

Mumz [18]

Answer: pH of a 0.500 M $HNO_2$ solution is 1.82

Explanation:

$HNO_2\rightarrow H^++NO_2^-$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.500 M and $\alpha$ = ?

$K_a=4.6\times 10^{-4}$

Putting in the values we get:

$4.6\times 10^{-4}=\frac{(0.500\times \alpha)^2}{(0.500-0.500\times \alpha)}$

$(\alpha)=0.030$

$[H^+]=c\times \alpha$

$[H^+]=0.500\times 0.030=0.015$

Also $pH=-log[H^+]$

$pH=-log[0.015]=1.82$

Thus pH of a 0.500 M $HNO_2$ solution is 1.82

3 0

3 years ago

2Fe(s) + O2(g) → 2FeO(s)<br><br><br> To which category does this reaction belong?

Varvara68 [4.7K]

Answer:

Redox reactions

Explanation:

Redox reactions consists of both oxidation and reduction

one species gets oxidised and other species become reduced, both oxidation and reduction happen simultaneously

reduction is either gain of electrons or gain of hydrogen. in reduction the oxidation number of species reduces

in this reaction the reduction half equation is

O₂ + 4e --> 2O²⁻

oxidation is either loss of electrons or gain of oxygen. in oxidation the oxidation number of species increases.

Fe --> Fe²⁺ + 2e

since both these half reactions happen overall its a redox reaction

6 0

3 years ago

Erbium metal (Er) can be prepared by reacting erbium(III) fluoride with magnesium; the other product is magnesium fluoride. Writ

Nesterboy [21]

Answer:

2ErF3 +3Mg = 3MgF2 + 2Er

Explanation:

This is a single replacement equation where there are 2 metals. The bonds are broken and new bonds are formed again by Mg and F.

Er has a +3 charge and F has a -1 charge. You switch it around and you get ErF3. Then you add the second reactant, Mg. The product is MgF as stated, and Mg has a charge of +2 and F has -1. You switch it again and you get MgF2. Then the second product Er is there.

Now we have

ErF3+Mg=MgF2+Er

So we balance the equation because of the law of conservation of mass.

Make F equal, so we add the coefficents 2 and 3

2ErF3+Mg=3MgF2+Er

And now Mg and Er need balancing so

2ErF3+3Mg=3MgF2+2Er

Hope this helped

8 0

4 years ago

If anybody known the answer plzz help me with this??​

If anybody known the answer plzz help me with this??