Reaction on positive electrode (cathode):
PbSO₄₍s₎ + 2H₂O₍l₎ → 2e⁻ + PbO₂₍s₎ + 4H⁺₍aq₎ + SO₄²⁻₍aq₎.
s - solid.
l - liquid.
aq - dissolve in water.
PbSO4 is converted to Pb at one electrode (anode) and to PbO₂ at the other (cathode). Lead battery can be recharged, during recharging, an external source of energy is used.
Answer:
d. 99.63% and 0.364%, respectively
Explanation:
The average mass of a nitrogen atom is 14.006 amu
14N-14.00307 amu with 0.9963 fractional abundance
1SN- 15.000108 amu with 0.00364 fractional abundance.
The relative abundance definition in chemistry is the percentage of a particular isotope that occurs in nature. The atomic mass listed for an element on the periodic table is an average mass of all known isotopes of that element.
In this problem, the fractional abundance has areaady been given. All we need to do now is convert them to percentage abundance.
14N-14.00307 = 0.9963* 100% = 99.63%
1SN- 15.000108 = 0.00364 * 100% = 0.364%
Answer:
to make sure the cholerie is not to high
For waves velocity (v) is equal to the wavelength (λ) times frequency (f). (They are inversely proportional)
V=λf
Since V is constant, if frequency increases, wavelength decreases.
It’s c because a wave cycle is repeating patterns all over again and again
