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lubasha [3.4K]
4 years ago
11

Which are the correct units for the mass rate reaction constant in the following kinetic expression TA=kCA2 Select one: a. hr1 □

d. L/(mg * hr)

Chemistry
1 answer:
aleksandr82 [10.1K]4 years ago
6 0

Which are the correct units for the mass rate reaction constant in the following kinetic expression: -r(_A) = k C(_A)^2

Select one:

a. hr^-1

b. mg/L

c. mg/(L*hr)

d. L/(mg * hr)

Answer: d. L/(mg * hr)

Explanation: The equation is a second order reaction. The figure attached shows the order of the reaction and the units alternatives.

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For H3PO4, Ka1 = 7.3 x 10^-3, Ka2 = 6.2 x 10^-6, and Ka3 = 4.8 x 10^-13. A 0.10 M aqueous solution of Na3PO4 therefore would be
zmey [24]

Answer:

The aqueous solution of Na_{3} Po_{4} therefore would be "strongly basic."

Explanation:

Strongly basic because the Na_{3} Po_{4} is completely an ionic compound. These compound can be 100% splitted into metal ions and hydroxide ion when used in the aqueous solution. Each moles dissolves which can give rise to mole of hydrogen ions when used in the solution. Whereas strong bases are not soluble in water as well.  in the presence of water equilibrium can also be achieved. A strong base has the capability which can just remove the proton from the molecule.

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Sliva [168]
Amount of copper= mass / molar mass = 17/64=0.2656
According to the balance equation, amount of hydrogen gas : amount of copper = 1:1
Therefore amount of hydrogen gas is 1:1
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3 years ago
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lianna [129]

Answer:

where it goes

Explanation:

3 0
3 years ago
Read 2 more answers
1. Mass is measured with and instrument called a _____
Brilliant_brown [7]
1.triple beam balance
4 0
3 years ago
Add a temperature of -33.0 Celsius a sample of a confirmed gas eggs or to pressure of 0.5 to 6 ATM if it's volume remains consta
Levart [38]

<u>Answer:</u> The final temperature of the gas is -220.6°C

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6atm\\T_1=-33^oC=[273-33]K=240K\\P_2=1.31atm\\T_2=?

Putting values in above equation, we get:

\frac{6atm}{240K}=\frac{1.31atm}{T_2}\\\\T_2=\frac{1.31\times 240}{6}=52.4K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

52.4=T(^oC)+273\\\\T(^oC)=-220.6^oC

Hence, the final temperature of the gas is -220.6°C

3 0
4 years ago
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