They filled 2s before 1s was filled.... 2p is innocent because you shouldn’t be left with an open space when you have a even number... and 3s comes before 2p
They are lost from valence shell (it's outermost shell of an atom).
->>> outside the atom
18 g of silicon-32 will be present in 800 years.
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and it's given by
where,
quantity of the substance remaining
the initial quantity of the substance
time elapsed
the half-life of the substance
From the given information we know:
The initial quantity of silicon-32 is 40 g.
The time elapsed is 800 years.
The half-life of silicone-32 is 710 years.
So, using the calculation above, we can determine how much silicon-32 is left.
Therefore,18 g of silicon-32 will be present in 800 years.
Learn more about half-life here:
brainly.com/question/25750315
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Colligative properties are usually used in relation to solutions.
Colligative properties are those properties of solutions, which depend on the concentration of the solutes [molecules, ions, etc.] in the solutions and not on the chemical nature of those chemical species. Examples of colligative properties include: vapour pressure depression, boiling point elevation, osmotic pressure, freezing point depression, etc.
For the question given above, the correct option is D. This is because the statement is talking about freezing point elevation, which is not part of colligative properties.
Answer is: 0.5 dm³ to dissolve.
m(CuSO₄) = 11.2 g.
c(CuSO₄) = 0.140 mol/dm³,
V(CuSO₄) = ?
n(CuSO₄) = m(CuSO₄) ÷ M(CuSO₄).
n(CuSO₄) = 11.2 g ÷ 159.6 g/mol.
n(CuSO₄) = 0.07 mol.
V(CuSO₄) = n(CuSO₄) ÷ c(CuSO₄).
V(CuSO₄) = 0.07 mol ÷ 0.14 mol/dm³.
V(CuSO₄) = 0.5 dm³.
