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3 years ago

Which statement best describes the compressibility of a gas?

1 answer:

7 0

The answer to the question stated above is:
 Gas is easily compressible because the molecules of a gas are much further apart than those of a solid.

characteristic properties of gases:

(1) they are easy to compress,

(2) they expand to fill their containers, and

(3) they occupy far more space than the liquids or solids from which they form.

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In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t

Arada [10]

Answer:

$\large\boxed{\large\boxed{0.529M}}$

Explanation:

Since the rate constant has units of s⁻¹, you can tell that the order of the reaction is 1.

Hence, the rate law is:

$r=d[A]/dt=-k[A]$

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

$[A]=[A]_0e^{-kt}$

You know [A]₀, k, and t, thus you can calculate [A].

$[A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}$

$[A]=0.529M$

7 0

3 years ago

which of the following is the name given to the pairs of valence electrons that do not participate in bonding in diatomic oxygen

Bond [772]

The answer to your question is

D: Unshared Pair

Hope this helps you :))))

6 0

3 years ago

What is the specific heat capacity of a metal if it requires 177.5 J to change the temperatures of 15.0g of the metal from 25.00

Vikentia [17]

Answer:

The specific heat capacity of a metal is 1.31 J/g°C = C

Explanation:

A classical excersise of calorimetry to apply this formula:

Q = m . C . ΔT

177.5 J = 15 g . C (34°C - 25°C)

177.5 J = 15g . 9°C . C

177.5 J /15g . 9°C = C

1.31 J/g°C = C

3 0

3 years ago

A student uses a calorimeter to determine the enthalpy of dissolving for ammonium nitrate. The student fills a calorimeter with

ale4655 [162]

Enthalpy change during the dissolution process = m c ΔT,

here, m = total mass = 475 + 125 = 600 g
c = specific heat of water = 4.18 J/g °C
ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)

Therefore, Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
= -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)

Thus, enthalpy of dissolving of the ammonium nitrate is -40630 J/g

7 0

3 years ago

Describe the main difference between the Bohr model of the atom and the Rutherford model.

atroni [7]

Answer:

The main difference between the two models was about the location of the electron in an atom.

Explanation:

Rutherford described that:

The electrons were outside of the nucleus.

They were equal in number to the "positiveness" of the nucleus.

Also, He randomly placed the negative electrons outside the nucleus.

Bohr improved the Rutherford model:

Bohr placed the electrons in distinct energy levels.

Electrons only exist in fixed orbitals (shells) and not anywhere in between.

Each shell has a fixed energy

Rutherford explained the nucleus of an atom, while Bohr was more into the electrons and their energy levels.

8 0

3 years ago

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