Answer: x = 14 and y = 10
Step-by-step explanation: What we have in the question is a pair of simultaneous equations as follows(
x = y + 4 ———(1)
2x - 3y = -2 ——(2)
Looking at both equations, one of the variables has a coefficient of 1, and as a result of that, we shall use the substitution method.
From equation (1), x = y + 4
Substitute for the value of x in equation (2)
2x - 3y = -2
2(y + 4) - 3y = -2
2y + 8 -3y = -2
-y + 8 = -2
Subtract 8 from both sides of the equation
-y +8 -8 = -2 -8
-y = -10
Divide both sides of the equation by -1
y = 10
Having calculated y, substitute for the value of y into equation (1)
x = y + 4
x = 10 + 4
x = 14
Therefore, x = 14 and y = 10
Answer:
oh.
Step-by-step explanation:
The answer is 11 i think
102-9=93%3=31
102-3=99%9=11
The given function is
f(x) = sec²x - sec²x sin²x
Note that
sin²x + cos²x = 1, so that 1 - sin²x = cos²x.
Also, sec(x) = 1/cos(x).
Therefore
f(x) = sec²x(1 - sin²x)
= sec²x cos²x
= 1
Answer:
The graph of the given function should be a constant value of 1.
The graph is shown below.
So, f(x) is a composite function. This means that g(x) is inside of h(x); in other words, you would substitute g(x) for x in h(x).
Something happened to g(x) (in the form of h(x)) to turn it into f(x). You should notice that f(x) is simply g(x) raised to the third power.
Therefore, h(x) = x^3
You can check this by working it backwards.
Start with: h(x) = x^3
Substitute: x = g(x) = 4x^2-11
Now you have: h(x) = (g(x))^3 = (4x^2-11)^3
Hope this helps!