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1 year ago

which dual-stack architecture allows ipv4 and ipv6 at the network layer to access a single tcp/udp stack

Computers and Technology

1 answer:

Archy [21]1 year ago

6 0

The dual-layer-IP allows ipv4 and ipv6 at the network layer to access a single tcp/udp stack.

<h3>What is the dual IP layer?</h3>

The word dual-stack is a word that connote a full or total duplication of all stages in the protocol stack ranging from its applications to the network layer.

Note that the dual-layer-IP method often gives room for a computer to run IPv4 and IPv6 simultaneously at the network layer, and all of the IP stack can access a different TCP/UDP stack.

Learn more about architecture from

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Turns on her laptop and gets the error message "OS NOT FOUND." She checks the hard disk for damage or loose cable, but that is n

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3 years ago

Graded Assignments may be found at the end of each chapter of the required textbook under the title "Real-World Exercises". Each

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Ok chapter 2 be done by 11:59

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3 years ago

def getCharacterForward(char, key): """ Given a character char, and an integer key, the function shifts char forward `key` steps

zhenek [66]

Answer:

def getCharacterForward(char, key):
charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
if(len(char) > 1):
return None
elif(not isinstance(key, int)):
return -1
else:
index = charList.find(char)
if(index + key <= 25):
return charList[index + key]
else:
return charList[(index + key)% 26]
print(getCharacterForward("C", 4))
print(getCharacterForward("X", 4))

Explanation:

Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.

Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).

Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).

However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).

We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:

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3 years ago

1:A presentation program which is developed by Microsoft

LekaFEV [45]

Option 3: PowerPoint.

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2 years ago

Read 2 more answers

In Java.Use a single for loop to output odd numbers, even numbers, and an arithmetic function of an odd and even number. Use the

rosijanka [135]

Answer:

<em>This program is written using java programming language</em>

<em>Difficult lines are explained using comments (See Attachment for Source file)</em>

<em>Program starts here</em>

import java.util.*;

import java.lang.Math;

public class oddeven{

public static void main(String [] args)

{

double even,odd;//Declare variables even and odd as double

//The next iteration prints odd numbers

for(int i = 1;i<=173;i+=2)

{

odd = i;

System.out.format("%.4f",odd);//Round to 4 decimal places and print

System.out.print("\t");

}

System.out.print('\n');//Start printing on a new line

//The next iteration prints even numbers

for(int i = 0;i<=173;i+=2)

{

even=i;

System.out.format("%.4f",even);//Round to 4 decimal places and print

System.out.print("\t");

}

System.out.print('\n');//Start printing on a new line

double ssqrt;//Declare ssqrt to calculate the square root of sum of even and odd numbers

for(int i = 0;i<=173;i+=2)

{

ssqrt = Math.sqrt(2*i+1);//Calculate square root here

System.out.format("%.4f",ssqrt); //Round to 4 decimal places and print

System.out.print("\t");

}

Explanation:

Libraries are imported into the program

import java.util.*;

import java.lang.Math;

The following line declares variables even and odd as double

double even,odd;

The following iteration is used to print odd numbers with in the range of 0 to 173

for(int i = 1;i<=173;i+=2) {

odd = i;

System.out.format("%.4f",odd); This particular line rounds up each odd numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The following iteration is used to print even numbers with in the range of 0 to 173

for(int i = 0;i<=173;i+=2)

{

even=i;

System.out.format("%.4f",even); This particular line rounds up each even numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The next statement declares ssqrt as double to calculate the square root of the sum of even and odd numbers

double ssqrt;

for(int i = 0;i<=173;i+=2)

{

ssqrt = Math.sqrt(2*i+1);This line calculates the square root of sum of even and odd numbers

System.out.format("%.4f",ssqrt); This particular line rounds up each even numbers to 4 decimal places before printing them