Question

Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bag_ounces followed by "seconds". End with a newline. Sample output with input: 7 42 seconds

Answer 1

Answer:

def print_popcorn_time(bag_ounces):

 if bag_ounces<3:

   print("Too Small")

 elif bag_ounces>10:

   print("Too Large")

 else:

   bag_ounces = bag_ounces*6

   print("%s Seconds\n" % bag_ounces)    

Explanation:

• Using Python Programming Language
• The function is defined to accept an int parameter
• Within the function body, if...elif and else statements are used to print the desired output
• note the use of the %s placeholder (formated output) and \n for a new line in the final print statement