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sleet_krkn [62]
3 years ago
9

A rectangular poster has an area of 190 inches squared. The height of the poster is one inch less than twice its width. Find the

dimension of the poster.
PLEASE SHOW ALL THE WORK!
Mathematics
1 answer:
Annette [7]3 years ago
4 0
Set the height to h, and the width to w.

We know that wh=190 and h=2w-1.

Substituting 2w-1 for h, we have:

w(2w-1)=190

So:
2w^2-w-190=0

Factoring this equation, we get (2w+19)(w-10)=0.  The solutions to this equation are -9.5 and 10, but clearly the width must be positive, Substituting 10 for the width, we get 10*2-1=19 for the height.
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3 years ago
In need of help plz <br> Find the ∠VXW and ∠XVW
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Answer:

∠VXW = 57°

∠XVW = 56°

Step-by-step explanation:

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Once we have this number, we need to remember a straight line also measures 180°. Line YW is important to find our answer, but first we need to find the answer to ∠WXZ. Since ∠YXZ and ∠WXZ come together and create the line YW, we can easily find the answer to ∠WXZ by subtracting ∠YXZ with 180; 180° - 57° = 123°

Now we need to find ∠VXW keeping the previous things I mentioned in mind; 180° - 123° = 57°. This is the answer to our first angle ∠VXW.

Since a triangle's angles always equal to 180° and we have the answer to two angles in △XVW, all we need to do is add then subtract;

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180° - 124° = 56°

And that is your answer!

∠VXW = 57°

∠XVW = 56°

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