<h3>
Answer: 110 degrees</h3>
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Work Shown:
x = measure of minor arc CL
angle J = ( (far arc) - (near arc) )/2
angle J = ((red arc) - (yellow arc))/2
angle J = ( (minor arc CL) - (minor arc CK) )/2
35 = ( x - 40 )/2
35*2 = x-40
70 = x-40
x-40 = 70
x = 70+40
x = 110
Minor arc CL = 110 degrees
Step-by-step explanation:
Your question is Incomplete please edit the question
3^1x3^1/3^1=3
Steps
3x1=3
3x1=3
3/3=3
Hope that helps
The central 50 percent of data around average
Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
