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2 years ago

Is there anyone that’s good with geometry? If so please help

Mathematics

2 answers:

Hitman42 [59]2 years ago

7 0

Answer:

where is your math problem?

Step-by-step explanation:

Let me know what the math problem is.

emmainna [20.7K]2 years ago

4 0

Answer:

im good at geometry :D

Step-by-step explanation:

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A robot can complete 4 tasks in 5/6

atroni [7]

I am the goddes of the air pods and the books of the laptops

4 0

2 years ago

Christina also plans on leaving her $10,000 invested for 20 years. Write an equation representing her investment’s value, y, aft

kaheart [24]

The required equation is y = 10000(1.0.25)^2x. The value of Christina’s investment after 20 years is $30,773.14

Compound interest

The interest accrued on a sum of money is known as interest. The formula for calculating the compound interest is expressed as:

y = y0(1+r/n)^nx

where

x is the time taken

r is the rate in decimal

n is the compounding time

Given the following

x = 20 years

n 2(semi annually)

r = 5.7% = 0.057

Substitute

y = 10000(1+0.057/2)^2(20)
y = 10,000(1 + 0.0285)^40

y = 10000(1.0285)^40
y = 30,773.14

Hence the value of Christina’s investment after 20 years is $30,773.14

Learn more on compound interest here: brainly.com/question/24924853

4 0

1 year ago

Dave collects U.S. gold coins. He has collection of 48 coins. Some are $10 coins, and the rest are $20 coins. If the face value

andrew11 [14]

Dave should slide some coins

7 0

2 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

2 years ago

What is the gradient between (0,3) and (1,8).

trasher [3.6K]

Step-by-step explanation:

Given

(x1 , y1) = ( 0 , 3)

(x2 , y2) = ( 1 , 8)

Now

Gradient =

$\frac{y2 - y1}{x2 - x1}$

$= \frac{8 - 3}{1 - 0} \\ = \frac{5}{1} \\ = 5$

Hope it will help :)

5 0

2 years ago