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astra-53 [7]
1 year ago
15

Which expression can be used to find the area of triangle rst? (8 ∙ 4) - one-half (10 12 16) (8 ∙ 4) - (10 12 16) (8 ∙ 4) - one-

half (5 6 8) (8 ∙ 4) - (5 - 6 - 8)
Mathematics
2 answers:
Ivenika [448]1 year ago
4 0

The area of the triangle RTS will be (8×4) - 1/2 (16+12+10). Then the correct option is A.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

We start by drawing a rectangle around the triangle as shown in the diagram below.

Area of the RST = area of the rectangle - (area of triangle A + area of triangle B + area of triangle C)

\rm Area\ of\ RST = (8 \times 4) - [(\dfrac{1}{2}  \times 8 \times 2) + (\dfrac{1}{2}  \times 4 \times 3) + (\dfrac{1}{2}  \times 5\times 2)]\\\\\\Area\ of\ RST = (8 \times 4) - \dfrac{1}{2} (16 + 12 + 10)

The area of the triangle RTS is (8×4) - 1/2 (16+12+10).

More about the geometry link is given below.

brainly.com/question/7558603

sp2606 [1]1 year ago
3 0

Answer:Option A

Step-by-step explanation:

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63.75

Step-by-step explanation:

255 divided by 4

7 0
2 years ago
Please help and explain!
Scrat [10]
K is the slope of the line formed by connecting the points.
Use slope formula:
\frac{y_2 - y_1}{x_2 - x_1}
where the 2 points are the end points of the line (First and last going Left to right)
(x_1,y_1) = (2,7)  \\ (x_2,y_2) = (8,28)
Substitute into slope formula
k= \frac{28-7}{8-2} = \frac{21}{6} = \frac{7}{2}
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5 0
3 years ago
How do you solve this problem? What is a rewritten form of the radical(-8/726) It is supposed to be a squar root sign instead of
Mamont248 [21]
I think the answer is negative 8 square root 726

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5 0
2 years ago
Please help me ASAP!!!
vovangra [49]
Answer is D the last one

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4 0
3 years ago
Look at the Hexagon below
Mama L [17]

Answer:

Angle 9: 60°

Angle 10: 30°

Side = radius = 40sqrt(x/3)

Area = [800sqrt(3)]x

Step-by-step explanation:

Total angle in a hexagon:

(6 - 2) × 180

720

Each interior angle:

720/6 = 120

angle 9 = 120/2 = 60

Angle 10 = 60/2 = 30

sin(60) = 20sqrt(x)/r

r = 20sqrt(x) ÷ sqrt(3)/2

r = 40sqrt(x/3)

Side:

sin(30) = ½s/(40sqrt(x/3))

½s = 20sqrt(x/3)

s = 40sqrt(x/3)

Area = (3sqrt(3))/2 × s²

Area = 3sqrt(3)/2 × 1600x/3

Area = [800sqrt(3)]x

4 0
3 years ago
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