3 years ago

write an equation of the line passing through the point (6,3) that is perpendicular to the line 5x - 6y = 10

Mathematics

1 answer:

Jlenok [28]3 years ago

3 0

Answer:

5x-6y-12=0

Step-by-step explanation:

...make y the subject y=-6/5x +2

...use the coefficient of x as the gradient,m=-6/5

...for a perpendicular line,find the negative reciprocal of the gradient,5/6

...sub into the eqn y= -1/m(x-a)+b

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Square root of 5u+2 = square root of 3u+14

alina1380 [7]

Sqrt(5u + 2) = sqrt(3u + 14)
Square both sides to clear the square root.
5u + 2 = 3u + 14
subtract 3u from both siides
2u + 2 = 14
subtract 2 from both sides
2u = 12
divide both sides by 2
u = 6
When you square a square root you MUST check the solution.
sqrt(5*6 + 2) = sqrt(3*6 + 14)
sqrt(32) = sqrt(32)

8 0

3 years ago

Simplify the polynomial. Then find its value for the given value of the variable.

vekshin1

Answer:

Step-by-step explanation:

Simplified expression:

$3x^3 -x^3 +5x^3-9x^3$