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KatRina [158]
3 years ago
14

Mr.Chen left $45,000 to his aunt when he died. This was 5% of his total worth. a) how much was Mr.Chen worth when he died? Show

your work. b) if his aunt had to pay 14% tax on the money she received, how much money would she be left with after taxes? Show your work.
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

A) Mr Chen was worth:

45,000/5 = 9,000

9,000 x 100 = 900,000

The answer is 900,00

You can also write this as an equation.

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The Sum Of Two Numbers Is 50 And The Difference Is 18. What Are The Numbers?
mart [117]
<span>The sum of two numbers is 50. The smaller number is 18 less than the larger number. What are the numbers?
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Equations:
x + y = 50
x = y - 18
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Add and solve for "x"::

2x = 32
x = 16
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Solve for "y"::
16 + y = 50
y = 34
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Hope I helped!

~Tomas</span>
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If d(x) = x2 - 7x - 7, find d(x - 1).​
satela [25.4K]

Answer: x^2-9x+1

Step-by-step explanation:

x^2-7x-7 d(x-1)

(you would just replace x to (x-1)

(x-1)^2-7(x-1)-7

(solve by square rooting (x-1)(x-1) then foil)

x^2-9x+1

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melisa1 [442]

Answer:

4.5

Step-by-step explanation:

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Please answer asap this is 7th grade math<br> find the area
Rainbow [258]

25pi

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