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I am Lyosha [343]
3 years ago
13

Brenda took her dog to the veterinarian for an exam. The doctor told Brenda her dog needed to lose weight. Her dog weighed 55 po

unds during this visit. The doctor suggested that her dog 45 pounds by their next visit. What is this weight decrease represented as a percent?
Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

<h2>18%</h2>

Step-by-step explanation:

Step one;

given

initial weight = 55 pounds

final weight= 45 pounds

Step two:

Required

the % weight decrease

% decrease= initial-final/initial *100

% decrease= 55-45/55 *100

% decrease= 10/55 *100

% decrease= 0.18 *100

% decrease= 18%

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meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

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Answer:

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Step-by-step explanation:

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Eva: 1(bag) + 11

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