You are given some ferrous iodide, fei2 , and are asked to extract the iron through electrolysis. what can be said about the mer
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Complete Question:
a) List the values that y may take on and construct the pdf table
b) Calculate the average expected matches over the long run of playing this game for the player
c) Calculate the average expected earnings over the long run of playing this game for the player
Answer:
a) Y = { -1, 1, 2,3}
E(X) = 0.5
c) There is a loss of $0.0802
Explanation:
a) Y will take on the values, Y = { -1, 1, 2,3}
The pdf table is attached as a file to this solution
b) E(X) = 0.5
c)
The average expected matches, E(X) = np
where p = 1/6, n =3
E(X) = 3 * 1/6
E(X) = 0.5
c) Average expected earnings =
P(y) can be seen from the pdf table in the file attached
Average expected earning = (-1*0.579) + (1*0.347) + (2*0.069) + (3 * 0.0046)
Average expected earning = -0.0802
This shows that instead of earning, there is a loss of $0.0802
The instantaneous velocity of the 15 kg. mass just after collision can be found by the principle of linear momentum.
a) The speed of the 15 kg. just after collision is <u>2 m/s</u>.
b) The type of collision is <u>inelastic collision</u>
c) The compression of the spring is approximately <u>0.323 m</u>.
Reasons:
The given parameters are;
Mass of the block attached to the spring, m₁ = 15.0 kg
Force constant of the spring, K = 575 N/m
Mass of the stone that strikes the block, m₂ = 3.00 kg
Speed of the stone, v₂ = 8.00 m/s
Speed with which the stone rebounds, v₃ = 2.00 m/s
a) The total initial momentum = 3 kg. × 8 m/s = 24 kg·m/s
The final momentum, just after collision = 3 × (-2) kg·m/s + 15 kg ×v₁
By conservation of momentum, we have;
24 kg·m/s = 3 × (-2) kg·m/s + 15 kg ×v₁
The speed of the 15 kg. just after collision, v₁ = <u>2 m/s</u>.
b) A collision is elastic when the kinetic energy of the collision is conserved
The initial kinetic energy, K.E.₁ = 0.5 × 3 kg. ×(8 m/s)² = 96 J
The sum of the final kinetic energy are;
0.5 × 3 kg. × (2 m/s)² + 0.5 × 15 kg × (2 m/s)² = 36 J
The initial kinetic energy ≠ The final kinetic energy
Therefore, <u>the collision is not elastic</u>
(c) The kinetic energy given by the block = The elastic potential energy gained by the spring
Kinetic energy of the block, K.E. = 0.5 × 15 kg × (2 m/s)² = 30 J
Elastic energy gained by the block = 0.5 × K × x² = 0.5 × 575 N/m × x²
Therefore;
0.5 × 575 N/m × x² = 30 J
The compression of the spring, <em>x</em> ≈ <u>0.323 m</u>.
Learn more here:
<em>Questions;</em>
<em>(a) The speed of the 15 kg mass immediately after the collision</em>.
<em>(b) Determine the type of collision; Elastic or inelastic collision</em>.
<em>(c) The distance to which the spring is compressed by the block</em>.