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2 years ago

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The diagram shows a square pizza box with side lengths of 18 inches. In the box is a circular pizza with a radius of 8 inches. W

hat is the difference between the area of box and the pizza?

1 answer:

kotegsom [21]2 years ago

5 0

There is a difference of 123 square inches between the pizza box and the pizza.

18x18=324
pi8^2=201.0619

324-201=123

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Which set of population data is the least dispersed from its mean? 2, 3, 2, 9 4, 0, 4, 0 6, 2, 2, 2 9, 3, 5, 3.

exis [7]

The set of data 6, 2, 2, 2 will have the least dispersion from its mean.

<h3 /><h3>What will be the mean?</h3>

From four sets of data, we take the mean of 6,2,2,2

$\rm mean =\dfrac{ Sum \ of\ data}{Number \ of\ data}$

So the mean will be

$\rm mean =\dfrac{ 6+2+2+2}{4}=\dfrac{12}{4} =3$

So the mean of the data (6,2,2,2) is 3 which has the least dispersion from its every data as compared to the other data

Thus the set of data 6, 2, 2, 2 will have the least dispersion from their mean.

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2 years ago

100 points!! <br> Please solve question 50 in detail

SCORPION-xisa [38]

Answer:

2.62

Step-by-step explanation:

$log_{b} \frac{b^{2}x^{\frac{5}{2} }}{\sqrt{y}}$

First, write the square root as exponent.

$log_{b} \frac{b^{2}x^{\frac{5}{2} }}{y^{\frac{1}{2}}}$

Move the denominator to the numerator and negate the exponent.

$log_{b}(b^{2}x^{\frac{5}{2}}y^{-\frac{1}{2}})$

Use log product property.

$log_{b}(b^{2}) + log_{b}(x^{\frac{5}{2}}) + log_{b}(y^{-\frac{1}{2}})$

Use log exponent property.

$2 log_{b}(b) + {\frac{5}{2}}log_{b}(x) - {\frac{1}{2}}log_{b}(y)$

Substitute values.

$2(1) + \frac{5}{2}(0.36) - \frac{1}{2}(0.56) \\2.62$

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3 years ago

Read 2 more answers

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute <em>h</em> in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for <em>d</em>, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

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3 years ago

Help please need asap!! Thank you

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Answer:

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Step-by-step explanation:

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2 years ago

Write the slope-intercept form of the equation of the line through the given points through {-3,1} and (-5,5)

Zigmanuir [339]

Slope = -2/1

work is provided in the image attached.

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3 years ago