Heres what we know
X=2006 goals
y= 2007 goals
497 = X +Y which can be arranged to be y= 497 - x
y= 37 + x
soooo..
we make the y equations equal to each other
37 + x = 497 - x
2x = 460
x= 230
now plug that back into the original equation to check
y = 37 + (230)
y = 267
so in 2006 (remember x represents 2006 goals) she made 230 goals
Answer:
yea
Step-by-step explanation:
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
The answer to 29×97 would be 2813
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