Multiply and simplify the product. 2i(4 – 5i) select the product. –2i 2i –10 8i 10 8i
1 answer:
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Answer:
The sample space is
{
}
Step-by-step explanation:
The sample space refers to the set of all the possible outcomes.
The possible outcomes are:
Head and blue ball: BH
Head and green ball: GH
Head and yellow ball: YH
Head and orange ball: OH
Tail and blue ball: BT
Tail and green ball: GT
Tail and yellow ball:YT
Tail and orange ball: OT
The sample space is
{
}
The answer is 19.4
Most of the time when you try to find a missing length of a right triangle you use Pythagorean theorem. Pythagorean theorem is A squared plus B squared equals C squared. C squared is always going to be the longest length/diagonal line otherwise known as your hypotenuse. In this case the ladder is the hypotenuse. So instead of adding five squared +20 squared you’re going to square 20 and then subtract five squared to get the missing length which would be B squared and then you have to find the square root of B squared. So 20 squared is 4000. 5squared is 25 400-25 = 375 square root of 375 is about 19.4.
Most of the time when you try to find a missing length of a right triangle you use Pythagorean theorem. Pythagorean theorem is A squared plus B squared equals C squared. C squared is always going to be the longest length/diagonal line otherwise known as your hypotenuse. In this case the ladder is the hypotenuse. So instead of adding five squared +20 squared you’re going to square 20 and then subtract five squared to get the missing length which would be B squared and then you have to find the square root of B squared. So 20 squared is 4000. 5squared is 25 400-25 = 375 square root of 375 is about 19.4.
Answer: The concentration of X is and the concentration of Y is
.
Step-by-step explanation:
Since we have given that
At 272 nm, absorbance = 0.215
At 327 nm, absorbance = 0.191
As we have given that
Compound X Compound Y
272 16400 3870
327 3990 6420
So, our equations becomes
By solving these two equations, we get that
Hence, the concentration of X is and the concentration of Y is
.