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Marina CMI [18]
3 years ago
8

Solve and graph inequality

Mathematics
1 answer:
alina1380 [7]3 years ago
4 0
Her sister could be about four or five
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Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
3 years ago
What is the least 10-digit whole number? write the number in word form and in standard form
Ghella [55]
1,000,000,000 standard form
one billion word form
7 0
3 years ago
Read 2 more answers
Which expression is equal to 4−−√40−3−−√45 ?
gregori [183]
The    Answer:   <span>−30<span>x                    .-. 
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6 0
3 years ago
A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable
Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

5 0
3 years ago
Find the equation of (2,-1)
Elis [28]
You seem to have forgotten to add in the y-intercept or slope. For the information you have given, it could be any equation, so long as it passes through the point (2, -1), such as
y = -x + 1
7 0
3 years ago
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