Question

To treat a burn on his hand, a person decides to place an ice cube on the burned skin. The mass of the ice cube is 10.0 g, and its initial temperature is − 12.6 ∘ C. The water resulting from the melted ice reaches the temperature of his skin, 30.2 ∘ C. How much heat is absorbed by the ice cube and resulting water? Assume that all of the water remains in the hand.

Answer 1

Answer:

$Q = 4859.152\,J$

Step-by-step explanation:

The heat absorbed by the ice cube is calculated by the following formula:

$Q = (10\,g)\cdot[(2.090\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (0^{\textdegree}C +12.2^{\textdegree}C)+334\,\frac{J}{g} + (4.186\,\frac{J}{kg\cdot ^{\textdegree}C})\cdot (30.2^{\textdegree}C-0^{\textdegree}C)]$

$Q = 4859.152\,J$