The angle ∠EJS is bisected by the diagonal JS to form an angle of 62°
Response:
<h3>What properties of a rhombus can be used to find ∠EJS = 62?</h3>
Properties of a rhombus:
The lengths of the sides of a rhombus are equal
The measure of the opposite angles of a rhombus are equal
The diagonals bisect the interior angles of a rhombus
Given that JOSE is a rhombus, and ∠ESO = 124°, we have;
∠EJO = ∠ESO = 124° opposite angles of a rhombus
∠EJS = ∠OJS definition of bisected angle ∠EJO
∠EJS + ∠OJS = ∠EJO by angle addition
- ∠EJS + ∠OJS = 2×∠EJS = ∠EJO = 124°

Learn more about a rhombus here:
brainly.com/question/10689502