If the second hand of a clock has a length of 10 cm, find the distance the tip of the second hand travels in 45 seconds. Give an
answer rounded to the nearest 100th.
1 answer:
The distance traveled by the second hand of the clock is 0.471 m.
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To calculate the distance the tip of the second hand of the clock travel in 45 seconds, we use the formula below.
<h3>Formula:</h3>
- L = 2πr∅/360.................. Equation 1
<h3> Where: </h3>
- L = distance traveled by the tip of the second hand.
- r = Length of the second hand
- ∅ = angle formed by the second hand of the clock
- π = pie
From the question,
<h3>Given:</h3>
- r = 10 cm = 0.1 m
- ∅ = (360×45/60) = 270°
- π = 3.14
Substitute these values into equation 1
- L = 0.1×2×270×3.14/360
- L = 0.471 cm.
Hence, The distance traveled by the second hand of the clock is 0.471 m
Learn more about distance traveled here: brainly.com/question/4931057
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